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NCERT Exemplar · Q11

Q.Consider a metal ring kept (supported by a cardboard) on top of a fixed solenoid carrying a current II. The centre of the ring coincides with the axis of the solenoid. If the current in the solenoid is switched off, what will happen to the ring?

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Switching the solenoid off makes the flux through the ring fall; by Lenz's law the ring's induced current is in the same sense as the solenoid current, so the two attract — the ring is pulled towards the solenoid (pressed onto the cardboard), not thrown up.

The induced current in the ring

While the solenoid carries a steady current II it produces an axial field; the ring, sitting on the axis just above it, links a flux Φ\Phi. When the current is switched off, Φ\Phi falls towards zero, so by Faraday's law an emf is induced in the ring:

ε=−dΦdt.\varepsilon = -\frac{d\Phi}{dt}.

By Lenz's law the induced ring current opposes the decrease of flux — it acts to keep the flux going in the original direction. That means the ring current circulates in the same sense as the solenoid's own current.

Force between the ring and the solenoid

Now compare the two: the top turns of the solenoid and the ring are like two coaxial loops carrying current in the same direction. Parallel currents in the same sense attract. Equivalently, the solenoid's field near its top end diverges outward (a radial component BrB_r), and Iring (dl⃗×B⃗)I_\text{ring}\,(d\vec l \times \vec B) for a same-sense ring current gives a net force towards the solenoid. …

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