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NCERT Exemplar · Q4

Q.Two circular coils A and B are placed side by side in the same plane a short distance apart, with A on the left and B on the right. Coil A carries a conventional current that circulates in the counterclockwise sense as seen by the reader. Coil A is now moved bodily towards the stationary coil B; while A is in motion a current is observed to flow in B, and this current stops the instant A stops moving. From these observations we can infer that:

(a) there is a constant current in the clockwise direction in A.
(b) there is a varying current in A.
(c) there is no current in A.
(d) there is a constant current in the counterclockwise direction in A.
Rajasthan RbseMCQ· 1mImportance★★★★★
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Coil B carries an induced current only during the interval when A is approaching it, and the current dies the moment A stops. That means the flux through B changes solely because the coils' separation changes, i.e. A's current is steady. Combined with the stated counterclockwise sense, the answer is (D).

Concept

An emf is induced in B whenever the magnetic flux linking B changes: εB=−dϕBdt\varepsilon_B=-\dfrac{d\phi_B}{dt}. The flux depends on the current in A through the mutual inductance MM, which itself depends on the separation between the coils: ϕB=M IA\phi_B=M\,I_A.

Why this decides the answer

dϕBdt=MdIAdt+IAdMdt.\frac{d\phi_B}{dt}=M\frac{dI_A}{dt}+I_A\frac{dM}{dt}.

  • The current in B starts when A starts moving and stops when A stops moving. Motion changes the separation, hence changes MM — this is the IAdMdtI_A\dfrac{dM}{dt} term.
  • Because the current in B is absent while A is stationary, the other term MdIAdtM\dfrac{dI_A}{dt} must vanish, i.e. dIAdt=0\dfrac{dI_A}{dt}=0. So the current in A is constant in time.

Eliminating the options …

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