NCERT Exemplar · Q21
Q.An infinitely long straight wire lies in the plane of the paper and carries a current I(t) whose rate of change dI/dt = λ is constant. A rectangular loop ABCD of wire, of resistance R, lies in the same plane with its two sides AB and DC (each of length l) parallel to the long wire. The nearer side DC is at a perpendicular distance x₀ from the wire and the farther side AB at a perpendicular distance x₀ + r (so the loop's breadth measured away from the wire is r). Find the magnitude of the current induced in the loop.
Rajasthan RbseSubjective· 3mImportance★★★★★
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Start your 14-day free trial to unlock the full solution →The long wire's field falls off as , so the flux through the loop is found by integrating across its breadth: . Since is constant, the induced emf is constant and .
Concept
The magnetic field of an infinitely long straight wire at perpendicular distance is
directed perpendicular to the loop's plane. Because varies across the loop, the flux must be obtained by integration.
Flux through the loop
Take a strip of width at distance , parallel to the wire and of length ; its area is . Integrating from the near side to the far side :
Induced emf and current …
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