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Worked Examples · Example 2.3

Q.Figures 2.8(a) and

(b) show the field lines of a positive and negative point charge respectively.
(a) Give the signs of the potential difference VP−VQV_P - V_Q; VB−VAV_B - V_A.
(b) Give the sign of the potential energy difference of a small negative charge between the points Q and P; A and B.
(c) Give the sign of the work done by the field in moving a small positive charge from Q to P.
(d) Give the sign of the work done by the external agency in moving a small negative charge from B to A.
(e) Does the kinetic energy of a small negative charge increase or decrease in going from B to A?
Figure 2.8
Figure 2.8
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A point charge gives V∝1/rV\propto 1/r, so potential falls with distance from a positive charge and rises (becomes less negative) with distance from a negative charge. With U=qVU=qV and Wfield=−ΔUW_{\text{field}}=-\Delta U, all the signs follow: (a) both differences >0>0;

(b) both PE differences >0>0;

(c) negative;

(d) positive; (e) KE decreases.

Concept understanding

Electric potential is a scalar equal to the work per unit positive charge to bring it from infinity. For a point charge,

V=14πε0qr,V=\frac{1}{4\pi\varepsilon_0}\frac{q}{r},

so for a positive charge VV is positive and decreases with rr (P nearer ⇒VP>VQ\Rightarrow V_P>V_Q), while for a negative charge VV is negative and becomes less negative with rr (B farther ⇒VB>VA\Rightarrow V_B>V_A). The potential energy of a test charge is U=qVU=qV, and the work done by the field is Wfield=−ΔUW_{\text{field}}=-\Delta U.

Part-by-part

(a) For the positive charge P is closer than Q, so VP>VQV_P>V_Q and VP−VQ>0V_P-V_Q>0. For the negative charge A is closer than B, so VAV_A is more negative, giving VB>VAV_B>V_A and VB−VA>0V_B-V_A>0.

(b) For a small negative test charge, U=qVU=qV with q<0q<0, so UU has the sign opposite to VV.

  • Q→\toP: VP>VQ⇒UP<UQV_P>V_Q\Rightarrow U_P<U_Q, so UQ−UP>0U_Q-U_P>0 — positive.
  • A→\toB: VB>VA⇒UB<UAV_B>V_A\Rightarrow U_B<U_A, so UA−UB>0U_A-U_B>0 — positive.

(c) Moving a positive charge from Q (lower VV) to P (higher VV) is against the field, so the field does negative work: Wfield=UQ−UP<0W_{\text{field}}=U_Q-U_P<0. …

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