Q.Obtain an expression for the magnetic field on the axis of a current carrying very long solenoid using Ampere's circuital law. Draw the necessary diagram.
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Start your 14-day free trial to unlock the full solution →Applying Ampere's circuital law to a rectangular Amperian loop, half inside and half outside a long solenoid, gives the uniform axial field B = mu_0 n I.
Setup: consider a long solenoid of turns per unit length carrying a steady current . For an ideal long solenoid, the magnetic field is essentially uniform and parallel to the axis inside the solenoid, and essentially zero just outside it.
Amperian loop: choose a rectangular loop such that side (length ) lies inside the solenoid parallel to the axis, side lies outside the solenoid (also parallel to the axis, where ), and the two sides , are perpendicular to the axis, partly inside and partly outside.
Applying Ampere's law, , around loop :
- Along (inside, parallel to ): contributes .
- Along (outside, where ): contributes . …
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