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Q.A circuit is shown in the figure by combining two NOT gates and one NOR gate. Write the truth table for this connected circuit.

inputs A and B each through a NOT gate into a NOR gate with output Y — Class 12 Physics semiconductor electronics question
Figure
Rajasthan RbseRajasthan Board Senior Secondary Examination 2022Subjective· 2mImportance★★★★★
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Feeding the complements of A and B into a NOR gate implements Boolean AND, by De Morgan's theorem — a standard 'universal gate' construction.

Let A′=A‾A' = \overline{A} (output of the first NOT gate) and B′=B‾B' = \overline{B} (output of the second NOT gate). These feed into a NOR gate, whose output is:

Y=A′+B′‾=A‾+B‾‾Y = \overline{A' + B'} = \overline{\overline{A} + \overline{B}}

By De Morgan's theorem, A‾+B‾‾=A⋅B\overline{\overline{A}+\overline{B}} = A \cdot B, so Y=A⋅BY = A \cdot B — the circuit implements the AND function.

Truth table:

| A | B | A' = Ā | B' = B̄ | A'+B' | Y = (A'+B')' |

|---|---|---|---|---|---| …

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