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Exercise 2.2 · Q12

Q.India is 9 hours and 30 minutes ahead of Ottawa ON, Canada. What is time in Canada when it is 1:25 am in India?

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Subtracting the 9 h 30 min time difference from 1:25 am in India (borrowing a day) gives 3:55 pm the previous day in Ottawa.

If Zone A is ahead of Zone B by Δt\Delta t, then Time in B=Time in A−Δt\text{Time in B} = \text{Time in A} - \Delta t (subtract, borrowing 2424 h / rolling back a calendar day if the result would be negative).

Given: India is ahead of Ottawa by Δt=9\Delta t = 9 h 3030 min; India time =1 ⁣: ⁣25=1\!:\!25 am (i.e., 01 ⁣: ⁣2501\!:\!25 in 24-hour form, same day).

  1. Express India's time on a 24-hour clock relative to midnight: 01 ⁣: ⁣2501\!:\!25.
  2. Subtract the time difference:

01 ⁣: ⁣25−09 ⁣: ⁣3001\!:\!25 - 09\!:\!30

Since 01 ⁣: ⁣25<09 ⁣: ⁣3001\!:\!25 < 09\!:\!30, borrow 2424 h from the previous day:

(24 ⁣: ⁣00+01 ⁣: ⁣25)−09 ⁣: ⁣30=25 ⁣: ⁣25−09 ⁣: ⁣30=15 ⁣: ⁣55(24\!:\!00+01\!:\!25) - 09\!:\!30 = 25\!:\!25 - 09\!:\!30 = 15\!:\!55 …

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