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Miscellaneous Exercise · Q11

Q.Number of divisors of 10,000,000 are:

(i) 7
(ii) 8
(iii) 49
(iv) 64
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Write 1000000010{}000{}000 in prime-factorised form and apply the divisor-counting formula to its exponents.

If N=p1a1p2a2⋯pkakN=p_1^{a_1}p_2^{a_2}\cdots p_k^{a_k} (prime factorisation), the number of positive divisors of NN is (a1+1)(a2+1)⋯(ak+1)(a_1+1)(a_2+1)\cdots(a_k+1).

  1. 10000000=10710{}000{}000=10^7.
  2. Since 10=2×510=2\times5, 107=(2×5)7=27×5710^7=(2\times5)^7=2^7\times5^7. …

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