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Problems · Problem 2.17

Q.What is the total number of orbitals associated with the principal quantum number n = 3?

Sikkim CbseNCERTSubjective· 2mImportance★★★★★est
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✓ Free question

Each principal quantum number nn contains n2n^2 orbitals. For n=3n = 3, there are 9 orbitals total (one 3s, three 3p, and five 3d).

Why n2n^2 orbitals?

The principal quantum number nn determines the shell, but within each shell electrons occupy different types of orbitals (subshells) with different shapes and orientations. The total number of orbitals isn't arbitrary—it emerges directly from the allowed values of the angular momentum quantum number ll and the magnetic quantum number mlm_l.

For a given nn, the angular momentum quantum number can take values l=0,1,2,…,(n−1)l = 0, 1, 2, \ldots, (n-1). Each value of ll defines a subshell (s, p, d, f, etc.), and within each subshell, the magnetic quantum number mlm_l ranges from −l-l to +l+l, giving (2l+1)(2l + 1) orbitals.

The total count is the sum over all allowed subshells:

Total orbitals=∑l=0n−1(2l+1)\text{Total orbitals} = \sum_{l=0}^{n-1} (2l + 1)

This sum always equals n2n^2—a beautiful result that connects quantum mechanics to simple arithmetic.

Counting orbitals for n=3n = 3

Let's work through the third shell systematically.

1. Identify allowed subshells

For n=3n = 3, the angular momentum quantum number ll can be 0,1,0, 1, or 22:

  • l=0l = 0 → 3s subshell
  • l=1l = 1 → 3p subshell
  • l=2l = 2 → 3d subshell

2. Count orbitals in each subshell

Each subshell contains (2l+1)(2l + 1) orbitals because mlm_l takes that many values:

Subshellllmlm_l valuesNumber of orbitals
3s001
3p1−1,0,+1-1, 0, +13
3d2−2,−1,0,+1,+2-2, -1, 0, +1, +25

3. Sum across all subshells

Total=1+3+5=9\text{Total} = 1 + 3 + 5 = 9

Alternatively, using the formula directly:

n2=32=9n^2 = 3^2 = 9

Tip

The pattern 1+3+5+…1 + 3 + 5 + \ldots (sum of the first nn odd numbers) always equals n2n^2. This is why the orbital count is so clean.

Watch out

Don't confuse the number of orbitals with the number of electrons. Each orbital can hold 2 electrons (spin up and spin down), so n=3n = 3 can accommodate up to 2n2=182n^2 = 18 electrons total.

✓Final answer

The total number of orbitals for n=3n = 3 is 9\boxed{9}.

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