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3.2 · Q10

Q.A firm knows that the price per unit 'p' for one of its product is linear. It also knows that it can sell 1400 units when the price is ₹4 per unit, and it can sell 1800 units at a price of ₹2 per unit. Find the price per unit if 'x' units are sold (or demanded). Also find the revenue function and the marginal revenue function.

Sikkim CbseNCERTSubjective· 3mImportance★★★★★
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The linear demand through (1400,4)(1400,4) and (1800,2)(1800,2) is p=11−x200p=11-\frac{x}{200}; revenue R=px=11x−x2200R=px=11x-\frac{x^2}{200} and marginal revenue R′=11−x100R'=11-\frac{x}{100}.

A linear price law p=mx+cp=mx+c with slope m=p2−p1x2−x1m=\dfrac{p_2-p_1}{x_2-x_1}; revenue R(x)=p⋅xR(x)=p\cdot x; marginal revenue MR=dRdxMR=\dfrac{dR}{dx}. Here (x1,p1)=(1400,4)(x_1,p_1)=(1400,4), (x2,p2)=(1800,2)(x_2,p_2)=(1800,2).

  1. Slope of the price line:

m=2−41800−1400=−2400=−1200.m=\frac{2-4}{1800-1400}=\frac{-2}{400}=-\frac{1}{200}.

  1. Point–slope form through (1400,4)(1400,4):

p−4=−1200(x−1400).p-4=-\frac{1}{200}(x-1400).

  1. Simplify:

p=4−x200+1400200=4−x200+7=11−x200.p=4-\frac{x}{200}+\frac{1400}{200}=4-\frac{x}{200}+7=11-\frac{x}{200}.

(Check: x=1800⇒p=11−9=2x=1800\Rightarrow p=11-9=2 ✓; x=1400⇒p=11−7=4x=1400\Rightarrow p=11-7=4 ✓.)

  1. Revenue function R(x)=p⋅xR(x)=p\cdot x: …

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