Skip to content
Check Your Progress · Q4

Q.A Cooperative Society of farmers has 50 hectares of land to grow two crops X and Y. The profit from crops X and Y per hectare are estimated as ₹ 10,500 and ₹ 9,000 respectively. To control weeds, a liquor herbicide has to be used for crops X and Y at rate of 20 liters and 10 liters per hectare. Further, no more than 800 liters of herbicide should be used in order to protect fish and wild life using a pond which collects drainage from this land. How much land should be allocated to each crop so as to maximize the total profit of the society? Formulate the above problem as linear programming problem.

Sikkim CbseNCERTSubjective· 3mImportance★★★★★
77% · 17/22 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

This is a resource allocation problem that can be modelled as a linear programming problem. The objective is to maximise profit from two crops subject to land and herbicide constraints. The final LPP formulation is: Maximise Z=10500x+9000yZ = 10500x + 9000y subject to x+y≤50x + y \leq 50, 20x+10y≤80020x + 10y \leq 800, x≥0x \geq 0, y≥0y \geq 0.

The core idea here is that you have limited resources (land and herbicide) and you want to decide how much of each crop to grow to get the highest possible profit. Linear programming gives you a mathematical way to express this — you write down what you want to maximise (the profit) and the restrictions you face (the constraints), all as linear equations or inequalities.

Let’s break it down step by step.

  1. Identify the decision variables

    These are the quantities you can control. Here, you decide how many hectares to allocate to each crop.

    Let:

    xx = number of hectares allocated to crop X

    yy = number of hectares allocated to crop Y

    Both xx and yy must be non-negative — you can’t allocate negative land.

  2. Write the objective function

    The goal is to maximise total profit. Profit per hectare for crop X is ₹ 10,500 and for crop Y is ₹ 9,000.

    So total profit ZZ is:

Z=10500x+9000yZ = 10500x + 9000y

We want to maximise ZZ.

  1. Formulate the constraints

    There are two main restrictions:

    • Land constraint: Total land available is 50 hectares. So:

x+y≤50x + y \leq 50

  • Herbicide constraint: Crop X uses 20 litres per hectare, crop Y uses 10 litres per hectare. Total herbicide used cannot exceed 800 litres. So:

20x+10y≤80020x + 10y \leq 800

  • Non-negativity constraints:

x≥0,y≥0x \geq 0, \quad y \geq 0

Watch out

A common mistake is to forget that the herbicide constraint is an inequality (≤), not an equation. You are allowed to use less than 800 litres — the limit is a maximum, not a requirement. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.