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Exercise 5 · Q3

Q.A cistern can be filled by pipes AA and BB in 4 hours and 6 hours respectively. When full, the cistern can be emptied by pipe CC in 8 hours. If all the pipes were turned on at the same time, in how much time will the cistern be filled?

Sikkim CbseNCERTSubjective· 2mImportance★★★★★
56% · 59/106 Questions
✓ Free question

Add the two inlet rates and subtract the outlet rate; the reciprocal of the net is 247\tfrac{24}{7} hours.

Net rate =1tA+1tB−1tC= \dfrac{1}{t_A} + \dfrac{1}{t_B} - \dfrac{1}{t_C} (outlet subtracts); time =1net rate= \dfrac{1}{\text{net rate}}.

  1. Rate of A=14A = \dfrac14, rate of B=16B = \dfrac16 (filling); rate of C=18C = \dfrac18 (emptying).
  2. Net rate =14+16−18= \dfrac14 + \dfrac16 - \dfrac18. LCD =24= 24: =624+424−324=724= \dfrac{6}{24} + \dfrac{4}{24} - \dfrac{3}{24} = \dfrac{7}{24} tank/h.
  3. Time to fill =17/24=247=337= \dfrac{1}{7/24} = \dfrac{24}{7} = 3\tfrac37 hours ≈3\approx 3 h 25.725.7 min.

Check: in 247\tfrac{24}{7} h, A+B−CA+B-C fill 247×724=1\tfrac{24}{7}\times\tfrac{7}{24} = 1 tank ✓.

✓Final answer

The cistern will be filled in 247=337\dfrac{24}{7} = 3\tfrac37 hours (about 33 hours 25.725.7 minutes).

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