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Exercise 6 · Q5

Q.AA runs 3 times as fast as BB. If AA gives BB a start of 40 metres, how far must the goal on the race course be so that AA and BB reach the goal at the same time?

Sikkim CbseNCERTSubjective· 3mImportance★★★★★
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Equal times with A thrice as fast: d3=d−40⇒d=60\dfrac{d}{3}=d-40\Rightarrow d=60 m.

Reach together ⇒\Rightarrow equal times: A’s distanceA’s speed=B’s distanceB’s speed\dfrac{\text{A's distance}}{\text{A's speed}}=\dfrac{\text{B's distance}}{\text{B's speed}}, where A's speed =3×=3\times B's speed.

  1. Let B's speed =v=v, then A's speed =3v=3v. Let the goal be dd metres from the start.
  2. A runs the full dd; B, with a 40 m start, runs d−40d-40.
  3. They reach together, so d3v=d−40v\dfrac{d}{3v}=\dfrac{d-40}{v}.
  4. Cancel vv: d3=d−40\dfrac{d}{3}=d-40. …

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