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Worked Examples · Example 27

Q.Two runners AA and BB complete a 100 metres race in 36 seconds and 48 seconds respectively, by how many metres will AA defeat BB?

Sikkim CbseNCERTSubjective· 3mImportance★★★★★
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AA finishes 100100 m in 3636 s; in that time BB (at 100100 m per 4848 s) covers only 7575 m, so AA wins by 2525 m.

Distance covered in a given time == speed ×\times time. Defeating distance =100−(distance run by B in A’s finishing time)=100-(\text{distance run by }B\text{ in }A\text{'s finishing time}).

  1. BB's speed =100 m48 s=2512=\dfrac{100\text{ m}}{48\text{ s}}=\dfrac{25}{12} m/s.
  2. AA finishes at t=36t=36 s. In 3636 s, BB covers 2512×36=25×3612=25×3=75\dfrac{25}{12}\times 36=\dfrac{25\times 36}{12}=25\times 3=75 m. …

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