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Exercise 1 · Q6

Q.If x(mod9)=2x \pmod 9 = 2, find all the possible values of xx; where 0<x<470 < x < 47.

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All xx with remainder 22 on division by 99 and 0<x<470<x<47 are 2,11,20,29,382, 11, 20, 29, 38.

x mod 9=2 ⟺ x=9k+2, k=0,1,2,…x \bmod 9 = 2 \ \Longleftrightarrow\ x = 9k + 2,\ k = 0,1,2,\dots

subject to 0<x<470 < x < 47.

  1. Generate values x=9k+2x = 9k+2:
kkx=9k+2x = 9k+2In (0,47)(0,47)?
02yes
111yes
220yes
329yes
438yes
547no (47≮4747 \not< 47)
  1. Apply the bound 0<x<470 < x < 47. x=47x=47 is excluded (strict inequality), so stop at 3838. …

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