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Chemistry · Ch 8 — Aldehydes, Ketones and Carboxylic Acids

Preparation of Aldehydes

8.2.2

Preparation of Aldehydes

1. From Acyl Chloride (Acid Chloride) — the Rosenmund Reduction

An acyl (acid) chloride can be hydrogenated directly to the corresponding aldehyde using hydrogen gas over a palladium catalyst that has been partially deactivated by depositing it on barium sulphate. This partial poisoning of the catalyst is deliberate: an ordinary, fully active palladium catalyst would keep reducing the product all the way to the alcohol, whereas the poisoned catalyst is just active enough to stop cleanly at the aldehyde. This reaction is named the Rosenmund reduction.

Rosenmund reduction: benzoyl chloride is hydrogenated over palladium on barium sulphate to give benzaldehyde, the drawn benzene-ring scheme printed in NCERT section 8.2.2.
Rosenmund reduction: benzoyl chloride is hydrogenated over palladium on barium sulphate to give benzaldehyde, the drawn benzene-ring scheme printed in NCERT section 8.2.2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (C, Cl, CHO) and reagent placement exactly as the textbook prints them. Every element of this display was checked against the printed page during the sweep's blind-judge verification pass, so what …

Benzoyl chloride is reduced by this method to benzaldehyde.

2. From Nitriles and Esters

A nitrile can be reduced with stannous chloride in the presence of hydrochloric acid; this first gives an imine, which is then hydrolysed to the aldehyde. This sequence is called the Stephen reaction.

RCN+SnCl2+HCl⟶RCH=NH→H3O+RCHO\text{RCN} + \text{SnCl}_2 + \text{HCl} \longrightarrow \text{RCH=NH} \xrightarrow{\text{H}_3\text{O}^+} \text{RCHO}

Alternatively, a nitrile can be reduced selectively with diisobutylaluminium hydride (DIBAL-H) to the imine stage, which is then hydrolysed to the aldehyde. "Selectively" matters here too: the reduction is controlled so it stops at the imine rather than running on to the amine.

RCN→2. H2O1. AlH(i-Bu)2R-CHO\text{RCN} \xrightarrow[2.\ \text{H}_2\text{O}]{1.\ \text{AlH(i-Bu)}_2} \text{R-CHO}

CH3 – CH=CH-CH2CH2-CN→2. H2O1. AlH(i-Bu)2CH3 – CH=CH-CH2CH2-CHO\text{CH}_3\text{ – CH=CH-CH}_2\text{CH}_2\text{-CN} \xrightarrow[2.\ \text{H}_2\text{O}]{1.\ \text{AlH(i-Bu)}_2} \text{CH}_3\text{ – CH=CH-CH}_2\text{CH}_2\text{-CHO}

Esters can be reduced the same way — DIBAL-H reduces an ester to the aldehyde stage, stopping short of the alcohol that a stronger reducing agent would give.

DIBAL-H reduction of an ester to an aldehyde: ethyl undecanoate CH3(CH2)9-CO-OC2H5, drawn with a vertical C=O double bond, reduced by DIBAL-H then water to the aldehyde CH3(CH2)9-CHO (NCERT section 8.2.2).
DIBAL-H reduction of an ester to an aldehyde: ethyl undecanoate CH3(CH2)9-CO-OC2H5, drawn with a vertical C=O double bond, reduced by DIBAL-H then water to the aldehyde CH3(CH2)9-CHO (NCERT section 8.2.2).

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (CH₃(CH₂)₉, C, OC₂H₅, H) and reagent placement exactly as the textbook prints them. Every element of this display was checked against the printed page during the sweep's blind-judge verification pass, so wh …

3. From Hydrocarbons — Aromatic Aldehydes

Aromatic aldehydes, such as benzaldehyde and its ring-substituted derivatives, are built up from aromatic hydrocarbons by three distinct routes.

(i) Oxidation of methylbenzene. A strong oxidising agent applied to toluene would normally carry the oxidation all the way to benzoic acid, so this route instead converts the methyl group into an intermediate that resists further oxidation, then hydrolyses that intermediate back to the aldehyde. Two reagents are used for this:

  • Chromyl chloride (CrO2Cl2\text{CrO}_2\text{Cl}_2) oxidises the methyl group of toluene, in carbon disulphide as solvent, to a chromium complex; hydrolysing this complex with aqueous acid gives benzaldehyde. This sequence is the Etard reaction.
Etard reaction: toluene plus chromyl chloride in carbon disulphide forms the chromium complex C6H5CH(OCrOHCl2)2, hydrolysed by H3O+ to benzaldehyde — the three drawn benzene-ring scheme of NCERT section 8.2.2.
Etard reaction: toluene plus chromyl chloride in carbon disulphide forms the chromium complex C6H5CH(OCrOHCl2)2, hydrolysed by H3O+ to benzaldehyde — the three drawn benzene-ring scheme of NCERT section 8.2.2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (CH₃, CH(OCrOHCl₂)₂, CHO) and reagent placement exactly as the textbook prints them. Every element of this display was checked against the printed page during the sweep's blind-judge verification pass, so wh …

  • Chromic oxide (CrO3\text{CrO}_3) in acetic anhydride converts toluene (or a substituted toluene), at 273–283 K, into benzylidene diacetate; hydrolysing this diacetate with aqueous acid on warming gives benzaldehyde.
Chromic oxide route: toluene with CrO3 in acetic anhydride at 273-283 K gives benzylidene diacetate C6H5CH(OCOCH3)2, hydrolysed with H3O+ on heating to benzaldehyde — drawn benzene-ring scheme, NCERT section 8.2.2.
Chromic oxide route: toluene with CrO3 in acetic anhydride at 273-283 K gives benzylidene diacetate C6H5CH(OCOCH3)2, hydrolysed with H3O+ on heating to benzaldehyde — drawn benzene-ring scheme, NCERT section 8.2.2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (CH₃, CH(OCOCH₃)₂, CHO) and reagent placement exactly as the textbook prints them. Every element of this display was checked against the printed page during the sweep's blind-judge verification pass, so wh …

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Side-chain chlorination then hydrolysis: toluene with Cl2/hv gives benzal chloride C6H5CHCl2, hydrolysed with water at 373 K to benzaldehyde — the commercial manufacture route, drawn benzene-ring scheme, NCERT section 8.2.2.
Side-chain chlorination then hydrolysis: toluene with Cl2/hv gives benzal chloride C6H5CHCl2, hydrolysed with water at 373 K to benzaldehyde — the commercial manufacture route, drawn benzene-ring scheme, NCERT section 8.2.2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (CH₃, CHCl₂, CHO) and reagent placement exactly as the textbook prints them. Every element of this display was checked against the printed page during the sweep's blind-judge verification pass, so wha …

Gatterman-Koch reaction: benzene treated with carbon monoxide and HCl over anhydrous AlCl3/CuCl gives benzaldehyde directly — drawn benzene-ring scheme, NCERT section 8.2.2.
Gatterman-Koch reaction: benzene treated with carbon monoxide and HCl over anhydrous AlCl3/CuCl gives benzaldehyde directly — drawn benzene-ring scheme, NCERT section 8.2.2.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your NCERT textbook's own diagram.

Redrawn from the NCERT page with the structures, printed labels (CHO) and reagent placement exactly as the textbook prints them. Every element of this display was checked against the printed page during the sweep's blind-judge verification pass, so what …