Q.A feasible region of a system of linear inequalities is said to be _________ if it can be enclosed within a circle.
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Start your 14-day free trial to unlock the full solution →The key idea is that a feasible region which can be enclosed within a circle is bounded — it does not extend infinitely in any direction. The answer is bounded.
Why This Matters: The Shape of Feasibility
When you solve a system of linear inequalities, the set of all points that satisfy every inequality is called the feasible region. This region can take two fundamental shapes:
- Bounded: The region is "closed in" — you can draw a circle (or any finite shape) around it, and the entire region lies inside. Think of a polygon or a triangle.
- Unbounded: The region stretches out to infinity in at least one direction. No matter how large a circle you draw, part of the region will always be outside it.
The question is asking for the word that describes a feasible region that can be enclosed within a circle. That word is bounded.
Step-by-Step Reasoning
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Understand the definition of "bounded" in geometry.
A set of points in the plane is called bounded if there exists some finite number such that the entire set lies inside a circle of radius centered at some point. In other words, you can "fence it in" with a finite boundary.
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Apply this to a feasible region.
A feasible region is the intersection of half-planes (from linear inequalities). If this intersection is a closed polygon (like a triangle, rectangle, or any shape with finite area), then you can always find a circle large enough to cover it. Such a region is bounded.
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Contrast with the opposite case. …
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