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Write Brief Answer · Q42

Q.Calculate the empirical and molecular formula of a compound containing 76.6% carbon, 6.38% hydrogen and the rest oxygen; its vapour density is 47.

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Step 1. %O = 100 − 76.6 − 6.38 = 17.02%.

Step 2. Relative moles: C = 76.6/12 = 6.383; H = 6.38/1 = 6.38; O = 17.02/16 = 1.064.

Step 3. Divide by the smallest (1.064): C = 6.00; H = 6.00; O = 1.00 -- empirical formula C6H6O, empirical-formula mass = 72+6+16 = 94.

Step 4. Molar mass from vapour density: molar mass = 2 × vapour density = 2 × 47 = 94 g mol⁻¹. …

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