Skip to content
Choose the Best Answer · Q11

Q.Which of these represents the correct order of their increasing bond order.

(a) C₂ < C₂²⁻ < O₂²⁻ < O₂
(b) C₂²⁻ < C₂⁺ < O₂ < O₂²⁻
(c) O₂²⁻ < O₂ < C₂²⁻ < C₂⁺
(d) O₂²⁻ < C₂⁺ < O₂ < C₂²⁻
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
25% · 21/84 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Bond order =(Nb−Na)/2= (N_b - N_a)/2 in each case.

Step 2. O₂²⁻ (2 more electrons than neutral O₂, both added to the antibonding π* level): Nb=8N_b = 8, Na=6N_a = 6 → BO =(8−6)/2=1= (8-6)/2 = 1.

Step 3. C₂⁺ (1 fewer electron than neutral C₂, removed from the bonding π level): Nb=7N_b = 7, Na=4N_a = 4 → BO =(7−4)/2=1.5= (7-4)/2 = 1.5.

Step 4. O₂ (neutral): Nb=10N_b = 10, Na=6N_a = 6 → BO =(10−6)/2=2= (10-6)/2 = 2. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.