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Question 67 of 71

Q.Which of the following is optically active ?

(a) Meso-tartaric acid
(b) 3-Chloropentane
(c) Glucose
(d) 2-Chloro propane
Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2025MCQ· 1mImportance★★★★★
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Glucose is optically active because its open-chain form has several carbon atoms each bonded to four different groups, with no internal symmetry to cancel the chirality; the other three options are all optically inactive.

Go through each option:

  1. Meso-tartaric acid: tartaric acid has two stereocentres, but the MESO form has an internal plane of symmetry that makes it superimposable on its own mirror image. Even though it has stereocentres, the internal symmetry makes it optically inactive (this is the classic example of a meso compound).
  2. 3-Chloropentane, CH3-CH2-CHCl-CH2-CH3: carbon 3 (bearing Cl) is attached to Cl, H, and two -CH2CH3 (ethyl) groups. Since the two ethyl groups are identical, carbon 3 is NOT a stereocentre (it needs four DIFFERENT groups), so this molecule is achiral/optically inactive. …

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