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Choose the Best Answer · Q25

Q.The correct equation for the degree of an associating solute, 'n' molecules of which undergoes association in solution, is

(a) α=n(i−1)n−1\alpha = \dfrac{n(i-1)}{n-1}
(b) α2=n(1−i)n−1\alpha^2 = \dfrac{n(1-i)}{n-1}
(c) α=n(i−1)1−n\alpha = \dfrac{n(i-1)}{1-n}
(d) α=n(1−i)n(1−i)\alpha = \dfrac{n(1-i)}{n(1-i)}
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
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Step 1. The text (section 9.11.2) states the degree of association is αassociation=n(1−i)n−1\alpha_{association}=\dfrac{n(1-i)}{n-1}.

Step 2. Take option (c), α=n(i−1)1−n\alpha=\dfrac{n(i-1)}{1-n}, and multiply both numerator and denominator by −1-1: n(i−1)×(−1)(1−n)×(−1)=n(1−i)n−1\dfrac{n(i-1)\times(-1)}{(1-n)\times(-1)}=\dfrac{n(1-i)}{n-1}.

Step 3. This is EXACTLY the book's own association formula from Step 1, so option (c) is algebraically identical to the correct expression. …

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