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Q.A sample of 12 M Concentrated hydrochloric acid has a density 1.2 gL−1^{-1}. Calculate the molality.

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Step 1. The concentrated HCl is 12 M, so 1 L of solution contains 12 mol of HCl. (Note: the density of concentrated HCl is standardly about 1.2 g/mL -- the printed 'gL−1^{-1}' is read here as g/mL, since a density of 1.2 g per LITRE would be far too low, close to that of a dilute gas, and physically inconsistent with a 12 M solution.)

Step 2. Mass of 1 L (1000 mL) of solution =1000 mL×1.2 g/mL=1200=1000\ \text{mL}\times1.2\ \text{g/mL}=1200 g. …

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