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Exercise 2.4 · Q3

Q.If α\alpha and β\beta are the roots of the quadratic equation x2+2x+3=0x^2+\sqrt2x+3=0, form a quadratic polynomial with zeroes 1α,1β\dfrac1\alpha,\dfrac1\beta.

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Step 1. From x2+2x+3=0x^2+\sqrt2x+3=0: α+β=−2\alpha+\beta=-\sqrt2, αβ=3\alpha\beta=3.

Step 2. New sum =1α+1β=α+βαβ=−23=\dfrac1\alpha+\dfrac1\beta=\dfrac{\alpha+\beta}{\alpha\beta}=\dfrac{-\sqrt2}3. New product =1αβ=13=\dfrac1{\alpha\beta}=\dfrac13.

Step 3. Required quadratic: x2−(new sum)x+(new product)=0⇒x2+23x+13=0x^2-(\text{new sum})x+(\text{new product})=0\Rightarrow x^2+\dfrac{\sqrt2}3x+\dfrac13=0.

Step 4. Multiply by 33 to clear fractions: 3x2+2x+1=03x^2+\sqrt2x+1=0.

✓Final answer

3x2+2x+1=03x^2+\sqrt2x+1=0.

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