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Exercise 4.5 · Q25

Q.1+3+5+7+⋯+171+3+5+7+\cdots+17 is equal to

(1) 101101
(2) 8181
(3) 7171
(4) 6161
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The series 1+3+5+⋯+171+3+5+\cdots+17 is the sum of the first nn odd numbers, where the last term 2n−1=172n-1=17.

Step 1. 2n−1=17⇒n=92n-1=17\Rightarrow n=9. …

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