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Exercise 11.13 · Q14

Q.∫x2+cos⁡2xx2+1csc⁡2x dx\displaystyle\int \dfrac{x^2+\cos^2x}{x^2+1}\csc^2x\,dx is

(1) cot⁡x+sin⁡−1x+c\cot x+\sin^{-1}x+c
(2) −cot⁡x+tan⁡−1x+c-\cot x+\tan^{-1}x+c
(3) −tan⁡x+cot⁡−1x+c-\tan x+\cot^{-1}x+c
(4) −cot⁡x−tan⁡−1x+c-\cot x-\tan^{-1}x+c
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Decompose the fraction to isolate a csc⁡2x\csc^2x piece and a 1/(x2+1)1/(x^2+1) piece.

Step 1. x2+cos⁡2xx2+1=(x2+1)+(cos⁡2x−1)x2+1=1−sin⁡2xx2+1\dfrac{x^2+\cos^2x}{x^2+1}=\dfrac{(x^2+1)+(\cos^2x-1)}{x^2+1}=1-\dfrac{\sin^2x}{x^2+1} (using cos⁡2x−1=−sin⁡2x\cos^2x-1=-\sin^2x). …

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