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Exercise 12.1 · Q5

Q.Eight coins are tossed once, find the probability of getting

(i) exactly two tails
(ii) at least two tails
(iii) at most two tails.
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
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Step 1. Sample space. 8 coins tossed: n(S)=28=256n(S)=2^8=256.

Step 2. Part (i) -- exactly 2 tails. n(A)=(82)=28n(A)=\binom82=28. P(A)=28256=764P(A)=\dfrac{28}{256}=\dfrac{7}{64}.

Step 3. Part (ii) -- at least 2 tails. Use the complement: P(at least 2 tails)=1−P(0 tails)−P(1 tail)=1−(80)+(81)256=1−1+8256=1−9256=247256P(\text{at least 2 tails})=1-P(0\text{ tails})-P(1\text{ tail})=1-\dfrac{\binom80+\binom81}{256}=1-\dfrac{1+8}{256}=1-\dfrac{9}{256}=\dfrac{247}{256}. …

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