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Exercise 12.1 · Q7

Q.A bag contains 7 red and 4 black balls, 3 balls are drawn at random. Find the probability that

(i) all are red
(ii) one red and 2 black.
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Step 1. Total ways. 7 red + 4 black = 11 balls; drawing 3: n(S)=(113)=165n(S)=\binom{11}{3}=165.

Step 2. Part (i) -- all 3 red. n(A)=(73)=35n(A)=\binom73=35. P(A)=35165=733P(A)=\dfrac{35}{165}=\dfrac{7}{33}. …

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