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Question 109 of 110

Q.If A=[0cbc0aba0]A = \begin{bmatrix}0 & c & b\\ c & 0 & a\\ b & a & 0\end{bmatrix}, compute A2A^2

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2026Subjective· 2mImportance★★★★★
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Multiplying A=[0cbc0aba0]A=\begin{bmatrix}0&c&b\\c&0&a\\b&a&0\end{bmatrix} by itself gives A2=[b2+c2abacaba2+c2bcacbca2+b2]A^2=\begin{bmatrix}b^2+c^2&ab&ac\\ab&a^2+c^2&bc\\ac&bc&a^2+b^2\end{bmatrix}.

Compute A2=A×AA^2=A\times A entry by entry, using row-by-column multiplication:

(1,1)(1,1): 0⋅0+c⋅c+b⋅b=c2+b20\cdot0+c\cdot c+b\cdot b=c^2+b^2

(1,2)(1,2): 0⋅c+c⋅0+b⋅a=ab0\cdot c+c\cdot0+b\cdot a=ab

(1,3)(1,3): 0⋅b+c⋅a+b⋅0=ac0\cdot b+c\cdot a+b\cdot0=ac

(2,1)(2,1): c⋅0+0⋅c+a⋅b=abc\cdot0+0\cdot c+a\cdot b=ab

(2,2)(2,2): c⋅c+0⋅0+a⋅a=c2+a2c\cdot c+0\cdot0+a\cdot a=c^2+a^2

(2,3)(2,3): c⋅b+0⋅a+a⋅0=bcc\cdot b+0\cdot a+a\cdot0=bc

(3,1)(3,1): b⋅0+a⋅c+0⋅b=acb\cdot0+a\cdot c+0\cdot b=ac

(3,2)(3,2): b⋅c+a⋅0+0⋅a=bcb\cdot c+a\cdot0+0\cdot a=bc …

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