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Question 98 of 110

Q.Find ∣A∣|A| if A=[0sin⁡αcos⁡αsin⁡α0sin⁡βcos⁡α−sin⁡β0]A = \begin{bmatrix} 0 & \sin\alpha & \cos\alpha \\ \sin\alpha & 0 & \sin\beta \\ \cos\alpha & -\sin\beta & 0 \end{bmatrix}.

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2022Subjective· 2mImportance★★★★★
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Expanding along the first row, every term cancels, giving ∣A∣=0|A|=0.

∣A∣=0⋅(0⋅0−sin⁡β⋅(−sin⁡β))−sin⁡α⋅(sin⁡α⋅0−sin⁡βcos⁡α)+cos⁡α⋅(sin⁡α⋅(−sin⁡β)−0⋅cos⁡α)|A| = 0\cdot(0\cdot0-\sin\beta\cdot(-\sin\beta)) - \sin\alpha\cdot(\sin\alpha\cdot0-\sin\beta\cos\alpha) + \cos\alpha\cdot(\sin\alpha\cdot(-\sin\beta)-0\cdot\cos\alpha)

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