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Question 158 of 175

Q.Find the range of the function 12cos⁡x−1\dfrac{1}{2\cos x - 1}.

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2023Subjective· 3mImportance★★★★★
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Letting u=2cos⁡x−1∈[−3,1]∖{0}u=2\cos x-1\in[-3,1]\setminus\{0\} and studying y=1/uy=1/u on the positive and negative parts of that interval gives the full range.

Since cos⁡x∈[−1,1]\cos x\in[-1,1], we get u=2cos⁡x−1∈[−3,1]u=2\cos x-1 \in [-3,1]. But u=0u=0 (i.e. cos⁡x=12\cos x=\tfrac12) must be excluded since it makes the denominator zero. So u∈[−3,0)∪(0,1]u\in[-3,0)\cup(0,1].

Let y=1uy=\dfrac1u.

For u∈(0,1]u\in(0,1]: as u→0+u\to0^+, y→+∞y\to+\infty; at u=1u=1, y=1y=1. So y∈[1,∞)y\in[1,\infty).

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