Skip to content
Question 168 of 175

Q.Find the range of the function f(x)=11−3cos⁡xf(x) = \dfrac{1}{1 - 3\cos x}

Tamil Nadu DgeTamil Nadu HSC First Year (DGE) Board 2025Subjective· 3mImportance★★★★★
96% · 168/175 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Find the range of the denominator first (excluding the zero that makes ff undefined), then invert it.

Let t=1−3cos⁡xt=1-3\cos x. Since cos⁡x∈[−1,1]\cos x\in[-1,1], we get 3cos⁡x∈[−3,3]3\cos x\in[-3,3], so t=1−3cos⁡x∈[1−3,1+3]=[−2,4]t=1-3\cos x\in[1-3,1+3]=[-2,4].

The function is undefined where t=0t=0, i.e. cos⁡x=13\cos x=\dfrac13 (which does occur), so we must exclude t=0t=0: t∈[−2,4]∖{0}t\in[-2,4]\setminus\{0\}.

Now f=1tf=\dfrac1t.

For t∈[−2,0)t\in[-2,0): as tt decreases from 0−0^- to −2-2, 1t\dfrac1t increases from −∞-\infty (at t→0−t\to0^-) to −12-\dfrac12 (at t=−2t=-2). So on this branch f∈(−∞,−12]f\in(-\infty,-\tfrac12]. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.