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Mathematics · Ch 6 — Two Dimensional Analytical Geometry

Two Parameters Families

6.4.7

Two Parameters Families

(iii) Both m,bm,b arbitrary. The full two-parameter family y=mx+by=mx+b (both constants free) is hard to visualise directly on a graph, but an important sub-case is easy: fixing a point (x1,y1)(x_1,y_1) and letting mm vary in y−y1=m(x−x1)y-y_1=m(x-x_1) sweeps out every non-vertical line through that one fixed point (the vertical line x=x1x=x_1 through the same point is the single member this point-slope parametrisation cannot express, since its slope would be undefined).

Family of lines through the intersection of two given lines. Let L1≡a1x+b1y+c1=0L_1\equiv a_1x+b_1y+c_1=0 and L2≡a2x+b2y+c2=0L_2\equiv a_2x+b_2y+c_2=0 be two given lines. Then, for a parameter λ\lambda,

L1+λL2=0L_1+\lambda L_2=0

is the equation of a family of straight lines, every member of which passes through the (fixed) point of intersection of L1=0L_1=0 and L2=0L_2=0 — because at that intersection point both L1=0L_1=0 and L2=0L_2=0 simultaneously, so L1+λL2=0+λ⋅0=0L_1+\lambda L_2=0+\lambda\cdot0=0 regardless of λ\lambda. Different real λ\lambda give different lines through that same fixed point. (This represents every line through the intersection except L2=0L_2=0 itself, which is the limiting case λ→∞\lambda\to\infty.)

Why this is useful: it lets a line through the intersection of L1,L2L_1,L_2 meeting one further condition be found without first solving for the intersection point — substitute the extra condition (a third point it must pass through, a required slope, etc.) directly into L1+λL2=0L_1+\lambda L_2=0, solve for λ\lambda, and substitute back. …

Figure 6.42Family through an intersection point

What this figure shows. Lines L1=0L_1=0 and L2=0L_2=0 crossing at (x0,y0)(x_0,y_0), with several members of the family L1+λL2=0L_1+\lambda L_2=0 (for λ=−2,12,2,…\lambda=-2,\tfrac12,2,\dots) drawn, all of them also passing through (x0,y0)(x_0,y_0). …