Q.Verify whether the following ratios are direction cosines of some vector or not.
(i) 51,53,54
(ii) 21,21,21
(iii) 34,0,43
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Concept understanding — Resolution of Vectors; Direction Cosines and Ratios
Resolving in the plane. Let i^,j^ be unit vectors along the positive x- and y-axes. Every position vector in the plane is written uniquely as OP=xi^+yj^,∣OP∣=x2+y2. More generally, if a,b are any two non-collinear vectors in a plane, every vector in that plane is a unique linear combination λa+μb.
Resolving in space. With i^,j^,k^ along the positive x,y,z axes, every position vector in space is uniquely OP=xi^+yj^+zk^,∣OP∣=x2+y2+z2. Three non-coplanar vectors a,b,c likewise span all of space uniquely: any vector is λa+μb+νc. The vector joining (x1,y1,z1) to (x2,y2,z2) has components (x2−x1)i^+(y2−y1)j^+(z2−z1)k^.
Matrix form.A=a1i^+a2j^+a3k^ can be written as the column a1a2a3; addition and scalar multiplication of vectors then match ordinary matrix addition and scalar multiplication component-by-component.
Direction cosines and direction ratios. For a point P(x,y,z) at distance r=x2+y2+z2 from the origin, let α,β,γ be the angles OP makes with the positive x,y,z axes (the direction angles). Then cosα=rx,cosβ=ry,cosγ=rz are the direction cosines of OP, usually written (l,m,n). Any triple proportional to (l,m,n) — such as (x,y,z) itself — is a set of direction ratios; unlike direction cosines, direction ratios are not unique.
Conversely, three numbers are the direction cosines of some vector iff the sum of their squares is 1 — this is exactly what you check to verify a given triple.
Any unit vector can be written as cosαi^+cosβj^+cosγk^.
Knowing only direction ratios or only direction cosines does not pin down a vector — you also need its magnitude.
A triple is a set of direction cosines iff the sum of its squares is exactly 1.
✓Final answer
None of (i),
(ii),
(iii) are direction cosines of any vector, since in each case l2+m2+n2=1.
Step 1. The test: (l,m,n) are the direction cosines of some vector iff l2+m2+n2=1.
Step 2 (i).(51)2+(53)2+(54)2=251+9+16=2526=1. Not direction cosines.
Step 3 (ii).(21)2+(21)2+(21)2=43=1. Not direction cosines.
Step 4 (iii).(34)2+02+(43)2=916+169=144256+81=144337=1; also 34>1, which alone is impossible for a cosine. Not direction cosines.
✓Final answer
All three fail the test l2+m2+n2=1, so none is a valid set of direction cosines.
Checking l+m+n=1 instead of the squared sum.
Not noticing a magnitude exceeding 1 (like 4/3) already rules a value out as a cosine.