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Exercise 8.2 · Q3

Q.Find the direction cosines and direction ratios for the following vectors.

(i) 3i^−4j^+8k^3\hat i-4\hat j+8\hat k
(ii) 3i^+j^+k^3\hat i+\hat j+\hat k
(iii) j^\hat j
(iv) 5i^−3j^−48k^5\hat i-3\hat j-48\hat k
(v) 3i^+4j^−3k^3\hat i+4\hat j-3\hat k
(vi) i^−k^\hat i-\hat k
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✓ Free question

Step 1. For a vector xi^+yj^+zk^x\hat i+y\hat j+z\hat k, its own components (x,y,z)(x,y,z) are already a set of direction ratios; dividing by r=x2+y2+z2r=\sqrt{x^2+y^2+z^2} gives the direction cosines.

Step 2 (i). 3i^−4j^+8k^3\hat i-4\hat j+8\hat k: DRs (3,−4,8)(3,-4,8), r=9+16+64=89r=\sqrt{9+16+64}=\sqrt{89}.

Step 3 (ii). 3i^+j^+k^3\hat i+\hat j+\hat k: DRs (3,1,1)(3,1,1), r=9+1+1=11r=\sqrt{9+1+1}=\sqrt{11}.

Step 4 (iii). j^\hat j: DRs (0,1,0)(0,1,0), r=1r=1, so the DCs are (0,1,0)(0,1,0) (it is already a unit vector).

Step 5 (iv). 5i^−3j^−48k^5\hat i-3\hat j-48\hat k: DRs (5,−3,−48)(5,-3,-48), r=25+9+2304=2338r=\sqrt{25+9+2304}=\sqrt{2338}.

Step 6 (v). 3i^+4j^−3k^3\hat i+4\hat j-3\hat k: DRs (3,4,−3)(3,4,-3), r=9+16+9=34r=\sqrt{9+16+9}=\sqrt{34}.

Step 7 (vi). i^−k^\hat i-\hat k: DRs (1,0,−1)(1,0,-1), r=1+0+1=2r=\sqrt{1+0+1}=\sqrt2.

✓Final answer

(i) (389,−489,889)\left(\tfrac3{\sqrt{89}},\tfrac{-4}{\sqrt{89}},\tfrac8{\sqrt{89}}\right) (ii) (311,111,111)\left(\tfrac3{\sqrt{11}},\tfrac1{\sqrt{11}},\tfrac1{\sqrt{11}}\right) (iii) (0,1,0)(0,1,0) (iv) (52338,−32338,−482338)\left(\tfrac5{\sqrt{2338}},\tfrac{-3}{\sqrt{2338}},\tfrac{-48}{\sqrt{2338}}\right) (v) (334,434,−334)\left(\tfrac3{\sqrt{34}},\tfrac4{\sqrt{34}},\tfrac{-3}{\sqrt{34}}\right) (vi) (12,0,−12)\left(\tfrac1{\sqrt2},0,\tfrac{-1}{\sqrt2}\right)

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