Q.Find the direction cosines of a vector whose direction ratios are
(i) 1,2,3
(ii) 3,−1,3
(iii) 0,0,7
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Concept understanding — Resolution of Vectors; Direction Cosines and Ratios
Resolving in the plane. Let i^,j^ be unit vectors along the positive x- and y-axes. Every position vector in the plane is written uniquely as OP=xi^+yj^,∣OP∣=x2+y2. More generally, if a,b are any two non-collinear vectors in a plane, every vector in that plane is a unique linear combination λa+μb.
Resolving in space. With i^,j^,k^ along the positive x,y,z axes, every position vector in space is uniquely OP=xi^+yj^+zk^,∣OP∣=x2+y2+z2. Three non-coplanar vectors a,b,c likewise span all of space uniquely: any vector is λa+μb+νc. The vector joining (x1,y1,z1) to (x2,y2,z2) has components (x2−x1)i^+(y2−y1)j^+(z2−z1)k^.
Matrix form.A=a1i^+a2j^+a3k^ can be written as the column a1a2a3; addition and scalar multiplication of vectors then match ordinary matrix addition and scalar multiplication component-by-component.
Direction cosines and direction ratios. For a point P(x,y,z) at distance r=x2+y2+z2 from the origin, let α,β,γ be the angles OP makes with the positive x,y,z axes (the direction angles). Then cosα=rx,cosβ=ry,cosγ=rz are the direction cosines of OP, usually written (l,m,n). Any triple proportional to (l,m,n) — such as (x,y,z) itself — is a set of direction ratios; unlike direction cosines, direction ratios are not unique.
Conversely, three numbers are the direction cosines of some vector iff the sum of their squares is 1 — this is exactly what you check to verify a given triple.
Any unit vector can be written as cosαi^+cosβj^+cosγk^.
Knowing only direction ratios or only direction cosines does not pin down a vector — you also need its magnitude.
Divide each direction ratio by r=x2+y2+z2 to get the direction cosines.
✓Final answer
(i) 141,142,143 (ii) 193,19−1,193 (iii) 0,0,1
Step 1. For direction ratios (x,y,z), the direction cosines are (rx,ry,rz) with r=x2+y2+z2.