Skip to content
III. Long Answer Questions · Q4

Q.Describe the total degrees of freedom for monoatomic molecule, diatomic molecule and triatomic molecule.

Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
21% · 15/71 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Monatomic. A single-atom molecule (e.g. He, Ne, Ar) has only translational motion along x, y, z: f=3f=3.

Step 2. Diatomic, normal temperature. Two atoms joined by a bond: 3 translational degrees of freedom (centre of mass motion) plus 2 rotational (about the two axes perpendicular to the bond; spin about the bond axis itself has negligible moment of inertia and doesn't count), giving f=3+2=5f=3+2=5.

Step 3. Diatomic, high temperature. At high temperature (~5000 K) vibration along the bond activates, contributing 2 more degrees of freedom (kinetic + potential energy of the vibration), giving f=5+2=7f=5+2=7.

Step 4. Linear triatomic. Three atoms on one straight line (e.g. CO2_2): rotationally identical to a diatomic molecule (only 2 rotational axes, since the third atom adds no moment of inertia about the shared axis), so f=5f=5 at normal temperature and f=7f=7 at high temperature (with vibration). …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.