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IV. Numerical Problems · Q5

Q.If 102010^{20} oxygen molecules per second strike 4 cm2^2 of wall at an angle of 30∘30^\circ with the normal when moving at a speed of 2×1032\times10^3 m s−1^{-1}, find the pressure exerted on the wall. (mass of one oxygen atom = 2.67×10−262.67\times10^{-26} kg)

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Step 1. Since the molecules striking the wall are oxygen MOLECULES (O2O_2), the mass to use is the molecular mass: m=2×(mass of one oxygen atom)=2×2.67×10−26=5.34×10−26 kgm=2\times(\text{mass of one oxygen atom})=2\times2.67\times10^{-26}=5.34\times10^{-26}\ \text{kg}.

Step 2. Only the component of velocity along the normal to the wall changes sign in the elastic collision, so the momentum change per molecule is 2mvcos⁡30∘2mv\cos30^\circ, where v=2×103 m s−1v=2\times10^3\ \text{m s}^{-1} and cos⁡30∘=0.866\cos30^\circ=0.866.

Step 3. Δpper molecule=2×5.34×10−26×2×103×0.866≈1.850×10−22 kg m s−1\Delta p_{\text{per molecule}}=2\times5.34\times10^{-26}\times2\times10^3\times0.866\approx1.850\times10^{-22}\ \text{kg m s}^{-1}. …

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