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Physics · Ch 1 — Nature of Physical World and Measurement

Application and Limitations of the Method of Dimensional Analysis

1.8.3

Application and Limitations of the Method of Dimensional Analysis

Dimensional analysis, built on the principle of homogeneity (1.8.2), has three practical applications -- and five genuine limits on what it can do.

  1. Converting a quantity from one system of units to another. Since the product of a quantity's numerical value nn and its unit [u][u] is a fixed physical quantity, n1[u1]=n2[u2]n_1[u_1]=n_2[u_2]. Writing a quantity's dimensions as aa in mass, bb in length, cc in time, and the two systems' base units as (M1,L1,T1)(M_1,L_1,T_1) and (M2,L2,T2)(M_2,L_2,T_2): n1[M1aL1bT1c]=n2[M2aL2bT2c]n_1[M_1^aL_1^bT_1^c]=n_2[M_2^aL_2^bT_2^c], so

    n2=n1(M1M2)a(L1L2)b(T1T2)c.n_2=n_1\left(\frac{M_1}{M_2}\right)^a\left(\frac{L_1}{L_2}\right)^b\left(\frac{T_1}{T_2}\right)^c.

    Worked example: convert GSI=6.6×10−11 N m2 kg−2G_{\text{SI}}=6.6\times10^{-11}\ \text{N m}^2\ \text{kg}^{-2} to CGS units. GG's dimensional formula is [M−1L3T−2][M^{-1}L^3T^{-2}], so a=−1,b=3,c=−2a=-1,b=3,c=-2. With M1=1M_1=1 kg, L1=1L_1=1 m, T1=1T_1=1 s (SI) and M2=1M_2=1 g =10−3=10^{-3} kg, L2=1L_2=1 cm =10−2=10^{-2} m, T2=1T_2=1 s (CGS): Gcgs=6.6×10−11×(103)−1×(102)3×1−2=6.6×10−11×10−3×106=6.6×10−8 dyne cm2 g−2G_{\text{cgs}}=6.6\times10^{-11}\times(10^3)^{-1}\times(10^2)^{3}\times1^{-2}=6.6\times10^{-11}\times10^{-3}\times10^{6}=6.6\times10^{-8}\ \text{dyne cm}^2\ \text{g}^{-2}.
  2. Checking the dimensional correctness of an equation. If every additive term reduces to the same dimensions, the equation is at least dimensionally consistent (though this does not guarantee it is numerically correct -- see limitation 5 below). Worked example: check v=u+atv=u+at: [LT−1]=?[LT−1]+[LT−2][T]=[LT−1]+[LT−1][LT^{-1}]\stackrel{?}{=}[LT^{-1}]+[LT^{-2}][T]=[LT^{-1}]+[LT^{-1}] -- both sides reduce to [LT−1][LT^{-1}], so the equation passes. Second example: check 12mv2=mgh\tfrac12mv^2=mgh: LHS =[M][LT−1]2=[ML2T−2]=[M][LT^{-1}]^2=[ML^2T^{-2}]; RHS =[M][LT−2][L]=[ML2T−2]=[M][LT^{-2}][L]=[ML^2T^{-2}] -- both sides match, so the equation is dimensionally correct.
  3. Establishing a relationship among physical quantities. If a quantity QQ is believed to depend on quantities Q1,Q2,Q3Q_1,Q_2,Q_3 as Q=k Q1aQ2bQ3cQ=k\,Q_1^aQ_2^bQ_3^c (with kk an unknown dimensionless constant), substituting each quantity's dimensional formula and matching powers of MM, LL, TT on both sides (using the principle of homogeneity) pins down aa, bb, cc -- though not kk itself. Worked example (simple pendulum): if the period TT depends on bob mass mm, string length ll, and gg, write T=k malbgcT=k\,m^al^bg^c. Dimensionally, [T]=[M]a[L]b[LT−2]c=[MaLb+cT−2c][T]=[M]^a[L]^b[LT^{-2}]^c=[M^aL^{b+c}T^{-2c}]; matching powers gives a=0a=0 (no MM on the LHS), −2c=1⇒c=−12-2c=1\Rightarrow c=-\tfrac12, and b+c=0⇒b=12b+c=0\Rightarrow b=\tfrac12. So T=k l1/2g−1/2=kl/gT=k\,l^{1/2}g^{-1/2}=k\sqrt{l/g} -- and experimentally k=2πk=2\pi, recovering the familiar T=2πl/gT=2\pi\sqrt{l/g}. Worked example (circular-motion force): if a force FF on a body moving in a circle of radius rr depends on mass mm, speed vv, and rr as F=k mavbrcF=k\,m^av^br^c (with k=1k=1): [MLT−2]=[M]a[LT−1]b[L]c=[MaLb+cT−b][MLT^{-2}]=[M]^a[LT^{-1}]^b[L]^c=[M^aL^{b+c}T^{-b}]; matching gives a=1a=1, −b=−2⇒b=2-b=-2\Rightarrow b=2, b+c=1⇒c=−1b+c=1\Rightarrow c=-1, so F=mv2r−1=mv2rF=mv^2r^{-1}=\dfrac{mv^2}{r} -- the familiar centripetal-force formula. Five limitations of dimensional analysis:
  1. It gives no information at all about dimensionless constants in a formula (like 1,2,…,π,e1,2,\ldots,\pi,e) -- these have to come from elsewhere (experiment or a full derivation).
  2. It cannot tell whether a given quantity is a vector or a scalar.
  3. It is not suitable for deriving relations that involve trigonometric, exponential or logarithmic functions, since these are dimensionless functions whose argument must be dimensionless -- the method has nothing to say about their internal structure. …