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I. Multiple Choice Questions · Q12

Q.If the force is proportional to square of velocity, then the dimension of proportionality constant is [JEE-2000]

(a) [MLT0^0]
(b) [MLT−1^{-1}]
(c) [ML−2^{-2}T]
(d) [ML−1^{-1}T0^0]
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Step 1. F=kv2⇒k=Fv2F=kv^2\Rightarrow k=\dfrac{F}{v^2}.

Step 2. [F]=[MLT−2][F]=[MLT^{-2}], [v2]=[LT−1]2=[L2T−2][v^2]=[LT^{-1}]^2=[L^2T^{-2}]. …

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