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III. Long Answer Questions · Q11

Q.Obtain an equation of continuity for a flow of fluid on the basis of conservation of mass.

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Step 1. Consider a pipe running from A to B, with cross-sectional area a1a_1 at a wide section and a2a_2 at a narrower section, carrying an incompressible, non-viscous liquid steadily at speeds v1v_1 and v2v_2 respectively.

Step 2. In a small time interval Δt\Delta t, the mass of fluid crossing the wide section (area a1a_1) is m1=(a1v1Δt)ρm_1=(a_1v_1\Delta t)\rho (the volume swept, a1v1Δta_1v_1\Delta t, times the density ρ\rho).

Step 3. Likewise, the mass crossing the narrow section (area a2a_2) in the same time interval is m2=(a2v2Δt)ρm_2=(a_2v_2\Delta t)\rho.

Step 4. Since the liquid is incompressible, mass can neither accumulate nor vanish anywhere between the two sections: conservation of mass requires m1=m2m_1=m_2: a1v1Δt ρ=a2v2Δt ρa_1v_1\Delta t\,\rho=a_2v_2\Delta t\,\rho. …

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