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III. Long Answer Questions · Q13

Q.Describe the construction and working of venturimeter and obtain an equation for the volume of liquid flowing per second through a wider entry of the tube.

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Step 1. Construction. A venturimeter consists of two wider tubes A and A' (cross-sectional area A) connected by a narrower throat tube B (cross-sectional area a), all carrying the flowing fluid of density ρ\rho. A U-tube manometer, containing a denser marker liquid of density ρm\rho_m, is connected between a point in the wide section and a point in the narrow throat.

Step 2. Working. As the fluid flows from the wide tube (speed v1v_1, pressure P1P_1) into the narrow throat (speed v2v_2, pressure P2P_2), the equation of continuity gives Av1=av2⇒v2=Aav1Av_1=av_2\Rightarrow v_2=\dfrac{A}{a}v_1. Applying Bernoulli's equation (horizontal flow, so height terms cancel): P1+12ρv12=P2+12ρv22=P2+12ρ(Aa)2v12P_1+\dfrac12\rho v_1^2=P_2+\dfrac12\rho v_2^2=P_2+\dfrac12\rho\left(\dfrac{A}{a}\right)^2v_1^2.

Step 3. Pressure difference. Rearranging: ΔP=P1−P2=12ρv12(A2a2−1)=ρv122⋅A2−a2a2\Delta P=P_1-P_2=\dfrac12\rho v_1^2\left(\dfrac{A^2}{a^2}-1\right)=\dfrac{\rho v_1^2}{2}\cdot\dfrac{A^2-a^2}{a^2}. This pressure drop is read off directly as the height difference h between the two arms of the manometer.

Step 4. Solving for the flow speed. Rearranging Step 3 for v1v_1: v12=2ΔP a2ρ(A2−a2)⇒v1=a2ΔPρ(A2−a2)v_1^2=\dfrac{2\Delta P\,a^2}{\rho(A^2-a^2)}\Rightarrow v_1=a\sqrt{\dfrac{2\Delta P}{\rho(A^2-a^2)}}. …

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