Q.Derive an expression for the elastic energy stored per unit volume of a wire.
Step 1. Consider a wire of un-stretched length L, cross-sectional area A, stretched (within the elastic limit, no energy lost) to a final extension l.
Step 2. The small work done in stretching the wire a further , at an intermediate extension , is , so the total work done from 0 to l is .
Step 3. Using Young's modulus, ; substituting, .
Step 4. Rewriting, : the elastic potential energy stored equals half the product of the final force and the final extension.
Step 5. Dividing by the wire's volume gives the energy density (energy per unit volume): , which, using stress = Y times strain (Hooke's law), can also be written .
The elastic energy stored per unit volume of a stretched wire is , derived by integrating using and dividing the total work by the wire's volume AL.
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