Skip to content

Business Mathematics and Statistics · Ch 4 — Differential Equations

Linear Differential Equations of the First Order

4

Linear Differential Equations of the First Order

The standard form and integrating factor

A first-order linear differential equation has the standard form

dydx+Py=Q\frac{dy}{dx}+Py=Q

where P,QP,Q are functions of xx alone (never of yy). Unlike the variable-separable case, yy and xx genuinely cannot be separated here — instead, multiplying through by the integrating factor

I.F.=e∫P dx\text{I.F.}=e^{\int P\,dx}

makes the left-hand side collapse into the derivative of a single product, ddx(y⋅I.F.)\frac{d}{dx}(y\cdot\text{I.F.}). The general solution is then

y⋅I.F.=∫Q⋅I.F. dx+Cy\cdot\text{I.F.}=\int Q\cdot\text{I.F.}\,dx+C

Worked reasoning

For dydx+y=ex\frac{dy}{dx}+y=e^x (so P=1,Q=exP=1,Q=e^x): I.F.=e∫1 dx=ex\text{I.F.}=e^{\int1\,dx}=e^x. The solution is

y⋅ex=∫ex⋅ex dx=∫e2x dx=e2x2+Cy\cdot e^x=\int e^x\cdot e^x\,dx=\int e^{2x}\,dx=\frac{e^{2x}}{2}+C

so y=ex2+Ce−xy=\frac{e^x}{2}+Ce^{-x}.

Note

The integrating factor is found from PP alone, never from QQ …

Definition 1Linear Differential Equation (First Order)

dydx+Py=Q\frac{dy}{dx}+Py=Q with P,QP,Q functions of xx alone; solved using the integrating factor I.F.=e∫P dx\text{I.F.}=e^{\int P\,dx}, giving $y\cdot\text{I.F.}=\in …