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Choose the Best Answer · Q5

Q.For the reaction 2NH3→N2+3H22NH_3 \rightarrow N_2 + 3H_2, if −d[NH3]dt=k1[NH3]-\dfrac{d[NH_3]}{dt}=k_1[NH_3], d[N2]dt=k2[NH3]\dfrac{d[N_2]}{dt}=k_2[NH_3], d[H2]dt=k3[NH3]\dfrac{d[H_2]}{dt}=k_3[NH_3] then the relation between k1,k2k_1,k_2 and k3k_3 is

(a) k1=k2=k3k_1=k_2=k_3
(b) k1=3k2=2k3k_1=3k_2=2k_3
(c) 1.5k1=3k2=k31.5k_1=3k_2=k_3
(d) 2k1=k2=3k32k_1=k_2=3k_3
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Step 1. For 2NH3→N2+3H22NH_3\rightarrow N_2+3H_2, the single unambiguous rate of reaction is Rate=−12d[NH3]dt=d[N2]dt=13d[H2]dt\text{Rate}=-\dfrac{1}{2}\dfrac{d[NH_3]}{dt}=\dfrac{d[N_2]}{dt}=\dfrac{1}{3}\dfrac{d[H_2]}{dt}.

Step 2. Substituting the given expressions −d[NH3]/dt=k1[NH3]-d[NH_3]/dt=k_1[NH_3], d[N2]/dt=k2[NH3]d[N_2]/dt=k_2[NH_3], d[H2]/dt=k3[NH3]d[H_2]/dt=k_3[NH_3]: 12k1[NH3]=k2[NH3]=13k3[NH3]\dfrac{1}{2}k_1[NH_3]=k_2[NH_3]=\dfrac{1}{3}k_3[NH_3], i.e. 12k1=k2=13k3\dfrac{1}{2}k_1=k_2=\dfrac{1}{3}k_3. …

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