Skip to content
Choose the Best Answer · Q6

Q.The decomposition of phosphine (PH3PH_3) on tungsten at low pressure is a first order reaction. It is because the (NEET)

(a) rate is proportional to the surface coverage
(b) rate is inversely proportional to the surface coverage
(c) rate is independent of the surface coverage
(d) rate of decomposition is slow
Tamil Nadu DgeTextbookSubjectiveImportance★★★★★
14% · 11/80 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1. Decomposition of PH3PH_3 on hot tungsten is a surface-catalysed (heterogeneous) reaction -- PH3PH_3 must first adsorb onto the tungsten surface before it decomposes, so the rate genuinely depends on how much of the surface is COVERED by adsorbed PH3PH_3, not directly on gas-phase concentration.

Step 2. At LOW pressure, the surface is far from saturated, so the fraction of surface covered (θ\theta) is directly proportional to the gas pressure P: θ∝P\theta\propto P. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.