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Question 67 of 69

Q.Identify compounds A, B and C in the following sequence of reaction. C6H5NO2→Sn/HClA→273 KNaNO2+HClB→CuCNCC_6H_5NO_2 \xrightarrow{Sn/HCl} A \xrightarrow[273\ K]{NaNO_2 + HCl} B \xrightarrow{CuCN} C

Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2025Subjective· 3mImportance★★★★★
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Nitrobenzene is reduced to aniline, diazotised in the cold to a diazonium salt, and then the diazonium group is replaced by −CN-CN using the copper-catalysed Sandmeyer reaction, giving benzonitrile.

Step 1 — formation of A: nitrobenzene is reduced to aniline using tin and concentrated hydrochloric acid (nascent hydrogen, [H][H]): C6H5NO2+6[H]→Sn/HClC6H5NH2 (A, aniline)+2H2OC_6H_5NO_2 + 6[H] \xrightarrow{Sn/HCl} C_6H_5NH_2\ (A,\ \text{aniline}) + 2H_2O

Step 2 — formation of B: aniline is treated with nitrous acid (generated in situ from NaNO2NaNO_2 and HClHCl) at a low temperature (273 K273\ K, i.e. 00–5°C5°C, to prevent decomposition), a diazotisation reaction giving benzenediazonium chloride: C6H5NH2+NaNO2+2HCl→273KC6H5N2+Cl− (B)+NaCl+2H2OC_6H_5NH_2 + NaNO_2 + 2HCl \xrightarrow{273K} C_6H_5N_2^+Cl^-\ (B) + NaCl + 2H_2O

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