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Question 58 of 58

Q.Mention the type of hybridisation in the following compounds.

(a) BrF5BrF_5
(b) BrF3BrF_3
Tamil Nadu DgeTamil Nadu HSC (DGE) Board 2026Subjective· 2mImportance★★★★★
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The hybridisation of the central bromine atom in each interhalogen compound is found by counting its total electron domains (bond pairs plus lone pairs) around it — 6 domains in BrF5BrF_5 giving sp3d2sp^3d^2, and 5 domains in BrF3BrF_3 giving sp3dsp^3d.

(a) BrF5BrF_5: bromine forms 5 σ\sigma-bonds to the 5 fluorine atoms, and has 1 lone pair remaining on it (since Br has 7 valence electrons; 7−5 (bonds)=27 - 5\ (\text{bonds}) = 2 electrons =1= 1 lone pair). Total electron domains =5+1=6= 5 + 1 = 6, requiring sp3d2sp^3d^2 hybridisation (giving an octahedral electron-pair arrangement, with the actual molecular shape being square pyramidal, since one octahedral position is occupied by the lone pair).

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