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Write Brief Answer · Q8

Q.What is the hybridisation of iodine in IF7? Give its structure.

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Step 1. Count the electron domains around iodine in IF7.

Iodine forms seven single bonds to seven fluorine atoms and retains no lone pair (iodine contributes 7 valence electrons, all used in the seven I-F bonds), so there are seven bonding electron domains around the central iodine atom.

Step 2. Determine the hybridisation.

Seven electron domains require seven hybrid orbitals, obtained by mixing one s, three p and three d orbitals: this is sp3d3 hybridisation.

Step 3. Determine the molecular geometry.

With seven bond pairs and zero lone pairs, VSEPR theory predicts a pentagonal bipyramidal geometry: five of the seven fluorine atoms lie in an equatorial plane, arranged as a regular pentagon around the iodine, while the remaining two fluorine atoms occupy axial positions directly above and below this plane. …

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