Skip to content

Mathematics · Ch 6 — Applications of Vector Algebra

Application of Dot and Cross Products in Geometry

6.3.3

Application of Dot and Cross Products in Geometry

Placing a convenient vertex at the origin turns several classical Euclidean-geometry theorems into short vector computations.

Apollonius's theorem (Example 6.6). If DD is the midpoint of side BCBC of △ABC\triangle ABC, taking AA as origin with AB⃗=b⃗, AC⃗=c⃗\vec{AB}=\vec b,\ \vec{AC}=\vec c gives AD⃗=b⃗+c⃗2\vec{AD}=\tfrac{\vec b+\vec c}{2} and BD⃗=c⃗−b⃗2\vec{BD}=\tfrac{\vec c-\vec b}{2}; computing ∣AD∣2+∣BD∣2|AD|^2+|BD|^2 and simplifying (the cross terms cancel) gives

∣AB⃗∣2+∣AC⃗∣2=2(∣AD⃗∣2+∣BD⃗∣2).|\vec{AB}|^2+|\vec{AC}|^2=2\big(|\vec{AD}|^2+|\vec{BD}|^2\big).

Concurrency of altitudes (Example 6.7). With the orthocentre OO as origin, OA⃗=a⃗,OB⃗=b⃗,OC⃗=c⃗\vec{OA}=\vec a,\vec{OB}=\vec b,\vec{OC}=\vec c. Since altitude AD⊥BCAD\perp BC means a⃗⋅(c⃗−b⃗)=0\vec a\cdot(\vec c-\vec b)=0, and altitude BE⊥CABE\perp CA means b⃗⋅(a⃗−c⃗)=0\vec b\cdot(\vec a-\vec c)=0; adding these two equations gives c⃗⋅(a⃗−b⃗)=0\vec c\cdot(\vec a-\vec b)=0, i.e. OC⃗⊥BA⃗\vec{OC}\perp\vec{BA} — so the perpendicular from CC to ABAB also passes through OO. All three altitudes meet at one point.

Medial-triangle area (Example 6.8). If D,E,FD,E,F are the midpoints of BC,CA,ABBC,CA,AB of △ABC\triangle ABC (origin at AA), a short computation with DE⃗,DF⃗\vec{DE},\vec{DF} shows area(△DEF)=14 area(△ABC)\text{area}(\triangle DEF)=\tfrac14\,\text{area}(\triangle ABC) — the medial triangle always has a quarter of the original's area. …

Figure 6.10Fig. 6.10 - Unit vectors a-hat = OA and b-hat = OB making angles alpha and beta with the positive x-axis; the angle between them is alpha-beta, used to prove sin(alpha-beta).
Fig. 6.10 — Fig. 6.10 - Unit vectors a-hat = OA and b-hat = OB making angles alpha and beta with the positive x-axis; the angle between them is alpha-beta, used to prove sin(alpha-beta).

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig. 6.10 - Unit vectors a-hat = OA and b-hat = OB making angles alpha and beta with the positive x-axis; the angle between them is alpha-beta, used to prove …

Figure 6.11Fig. 6.11 - Triangle ABC with D the midpoint of BC and median AD; position vectors AB = b and AC = c taken with A as origin (Apollonius' theorem).
Fig. 6.11 — Fig. 6.11 - Triangle ABC with D the midpoint of BC and median AD; position vectors AB = b and AC = c taken with A as origin (Apollonius' theorem).

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig. 6.11 - Triangle ABC with D the midpoint of BC and median AD; position vectors AB = b and AC = c taken with A as origin (Apolloniu …

Figure 6.12Fig. 6.12 - Triangle ABC with altitudes AD, BE and CF concurrent at the orthocentre O; position vectors a = OA, b = OB, c = OC used to prove concurrency.
Fig. 6.12 — Fig. 6.12 - Triangle ABC with altitudes AD, BE and CF concurrent at the orthocentre O; position vectors a = OA, b = OB, c = OC used to prove concurrency.

Drawn by us to help you understand the concept clearly, and verified to make sure it's accurate. For exams, practice from your textbook's own diagram.

What this figure shows. Fig. 6.12 - Triangle ABC with altitudes AD, BE and CF concurrent at the orthocentre O; position vectors a = OA, b = OB, c = OC used to prove …