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Exercise 8.8 · Q7

Q.If we measure the side of a cube to be 44 cm with an error of 0.10.1 cm, then the error in our calculation of the volume is

(1) 0.40.4 cu.cm
(2) 0.450.45 cu.cm
(3) 22 cu.cm
(4) 4.84.8 cu.cm
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Differential of volume V=x3V=x^3 is dV=3x2 dxdV=3x^2\,dx; substitute x=4,dx=0.1x=4,dx=0.1.

Step 1. Differentiate. V′(x)=3x2V'(x)=3x^2, so dV=3x2 dxdV=3x^2\,dx. …

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